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Barnsdall is a city in Osage County, Oklahoma, United States. The population was 1,325 at the 2000 census. Barnsdall is located at 36°33′34″N, 96°9′40″W (36.559344, -96.161062)[US Gazetteer files: 2000 and 1990. United States Census Bureau (2005-05-03). Retrieved on 2008-01-31.]. According to the United States Census Bureau, the city has a total area of 0.6 square miles (1.6 km²), all of it land. As of the census[American FactFinder. United States Census Bureau. Retrieved on 2008-01-31.] of 2000, there were 1,325 people, 542 households, and 357 families residing in the city. The population density was 2,195.3 people per square mile (852.6/km²). There were 630 housing units at an average density of 1,043.8/sq mi (405.4/km²). The racial makeup of the city was 74.26% White, 15.62% Native American, 0.30% Asian, 0.23% from other races, and 9.58% from two or more races. Hispanic or Latino of any race were 1.81% of the population.
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